A body of $10 K g$ is acted by a force of $129.4 N$ if $g$ $m / s e c^{2}$ . The acceleration of the block is $10 m / s^{2}$ . What is the coefficient of kinetic friction:

0.03

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0.01

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0.30

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0.25

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Solution

The correct option is C $0.30$
Given that,
Mass $m = 10 k g$
Force $F = 129.4 N$
Acceleration $a = 10 m / s$
Now, the coefficient of kinetic friction
$F - f_{k} = m a$
$F - μ m g = m a$
$- μ m g = m a - F$
$- μ = \frac{m a - F}{m g}$
$- μ = \frac{10 \times 10 - 129.4}{10 \times 9.8}$
$μ = 0.3$
Hence, the coefficient of kinetic friction is $0.3$

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