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Question

# A body of a mass 2 kg moving with a velocity (^i+2^j−3^k) m/s collides with another body of mass 3 kg moving with a velocity (2^i+^j+^k) m/s. If they stick together, the velocity in m/s of the composite body is

A
15(8i+7j3k)
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B
15(4^i+^j3^k)
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C
15(5^i+^j^k)
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D
15(4^i+8^j3^k)
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Solution

## The correct option is A 15(8i+7j−3k)We know that p=mvSo, p1=2(^i+2^j−3^k)kgm/s=(2^i+4^j−6^k)kgm/sand p2=3(2^i+^j+^k)kgm/s=(6^i+3^j+3^k)kgm/sResultant momentum isp=p1+p2=(2^i+4^j−6^k)+(6^i+3^j+3^k)=(8^i+7^j−3^k)kgm/sTotal mass(m) =2+3=5kgTherefore, the velocity of body isv=pm=15(8^i+7^j−3^k)m/s=15(8^i+7^j−3^k)m/s

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