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Standard XII

Physics

Accelerating Containers

A body of den...

Question

A body of density $2.5 g / c m^{3}$ is let free in a liquid of density $1.25 g / c m^{3}$ . the downward acceleration of the body while sinking in the liquid is ______.

790 c m / s^{2}

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490 c m / s^{2}

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590 c m / s^{2}

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690 c m / s^{2}

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Solution

The correct option is C $490 c m / s^{2}$
Here the body experiences buoyant force and gravitational force,

$F_{n e t} = m g - V ρ_{L} g = m a$

$a = g - \frac{V}{m} ρ_{L} g = g (1 - \frac{ρ_{L}}{ρ}) = \frac{g}{2}$

$a = 4.9 m / s^{2} = 490 c m / s^{2}$

Option $B$ is the correct answer.

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A body of density 2.5g/cm3 is let free in a liquid of density 1.25g/cm3. the downward acceleration of the body while sinking in the liquid is ______.

The correct option is C 490cm/s2Here the body experiences buoyant force and gravitational force,Fnet=mg−VρLg=maa=g−VmρLg=g(1−ρLρ)=g2a=4.9m/s2=490cm/s2Option B is the correct answer.

A body of density $2.5 g / c m^{3}$ is let free in a liquid of density $1.25 g / c m^{3}$ . the downward acceleration of the body while sinking in the liquid is ______.

The correct option is C $490 c m / s^{2}$
Here the body experiences buoyant force and gravitational force,

$F_{n e t} = m g - V ρ_{L} g = m a$

$a = g - \frac{V}{m} ρ_{L} g = g (1 - \frac{ρ_{L}}{ρ}) = \frac{g}{2}$

$a = 4.9 m / s^{2} = 490 c m / s^{2}$

Option $B$ is the correct answer.