A body of density?d?1??is balanced by a body of ?weight Mg and density d2?when both the bodies are fully submerged in a liquid of density d. The true mass of body is.

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Solution

Dear student
m be the mass of the body in vacuum
Actual weight - upthrust due to displaced air = Actual weight - Upthrudt due to air
$m g - (\frac{M}{d_{1}}) d g = M g - (\frac{M}{d_{2}}) d g m = \frac{M (1 - \frac{d}{d_{2}})}{(1 - \frac{d}{d_{1}})}$
regards

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A body of density?d?1??is balanced by a body of ?weight Mg and density d2?when both the bodies are fully submerged in a liquid of density d. The true mass of body is.

Dear student m be the mass of the body in vacuum Actual weight - upthrust due to displaced air = Actual weight - Upthrudt due to air mg - (Md1)dg = Mg -(Md2)dg m =M(1-dd2)(1-dd1) regards

Dear student
m be the mass of the body in vacuum
Actual weight - upthrust due to displaced air = Actual weight - Upthrudt due to air
$m g - (\frac{M}{d_{1}}) d g = M g - (\frac{M}{d_{2}}) d g m = \frac{M (1 - \frac{d}{d_{2}})}{(1 - \frac{d}{d_{1}})}$
regards