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Question

A body of density ρ floats with a volume V1 of its total volume V immersed in one liquid of density ρ1 and with the remainder of volume V2 immersed in another liquid of density ρ2 where. ρ1>ρ2 find V1 and V2

A
V1=V(ρρ2ρ1ρ2)V2=V(ρ1ρρ1ρ2)
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B
V1=V(ρ1ρ2ρ1ρ),V2=V(ρ1ρρ1ρ2)
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C
V1=V(ρρ2ρ1ρ),V2=V(ρ1ρ2ρρ2)
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D
V1=V(ρρ2ρ1ρ),V2=V(ρρ2ρρ1)
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Solution

The correct option is A V1=V(ρρ2ρ1ρ2)V2=V(ρ1ρρ1ρ2)
According to question..............
Giventhedensityofthebody=ρandvolume=VThereforethemassofthebody=VρForafloatingbodyintwoliquids,Weightofthebody=Buoyantforceofliquid1+Buoyantforceofliquid2Weightofthebody=VρgGiven,volumeofbodyimmersedinliquidofdensityρ1=V1and,volumeofbodyimmersedinliquidofdensityρ2=V2therefore,Buoyantforceofliquid1=V1ρ1g[accordingtothelawoffloatation.Buoyantforceofliquid2=V2ρ2gWeightofthebody=Buoyantforceofliquid1+Buoyantforceofliquid2Vρg=V1ρ1g+V2ρ2gVρ=V1ρ1+V2ρ2(i)V=V1+V2(ii)now,multiplyingequ(ii)withρ2.weget,Vρ2=V1ρ2+V2ρ2(iii)Now,subtractingequ(iii)fromequ(i).weget,VρVρ2=[V1ρ1+V2ρ2][V1ρ2+V2ρ2]V(ρρ2)=V1ρ1V1ρ2V(ρρ2)=V1(ρ1ρ2)V1=(ρρ2ρ1ρ2)V(A)similarly,onmultiplyingequ(ii)byρ1.weget,Vρ1=V1ρ1+V2ρ1(4)subtractingequ(4)fromequ(ii).weget,Vρ1Vρ=[V1ρ1+V2ρ1][V1ρ1+V2ρ2]V(ρ1ρ)=[V2ρ1V2ρ2]V(ρ1ρ)=V2[ρ1ρ2]V2=(ρ1ρρ1ρ2)V(B)so,thatthecorrectoptionisA.

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