Question

A body of dimensions $2m\times 3m\times 4m$ is acted upon by a force of 50N on the top surface $(2m\times 3m)$. The pressure due to the force on that surface is

• A. Pa
• B. Pa
• C. $\frac{10}{6}Pa$
• D. $\frac{50}{3}Pa$

Answer 1

The correct option is B

Pa

This body could be taken as a cuboid of dimensions $2m\times 3m\times 4m$. Therefore, the area of the top surface is $2m\times 3m=6m^2$.

Thus, $Pressure=\frac{Force}{area}=\frac{50}{2\times 3}=\frac{50}{6}Pa$.