Question

A body of dimensions $2m\times 3m\times 4m$ is acted upon by a force of $50N$ on the top surface $(2m\times 3m)$. The pressure due to the force on that surface is $\frac{50}{6}Pa$

• A. Pa
• B. Pa

Answer 1

The correct option is A

Pa

This body could be taken as a cuboid of dimensions $2m\times 3m\times 4m$.

Therefore, the area of the top surface is $2m\times 3m=6m^2$.

Force applied $F$ = $50N$

Thus, $pressure=\frac{Force}{area}=\frac{50}{6}Pa$.​