Question

A body of dimensions $2m\times 3m\times 4m$ is acted upon by a force of $50N$ on the top surface $(2m\times 3m)$. The pressure due to the force on that surface is

• A. Pa
• B. Pa
• C. $\frac{50}{7}Pa$.
• D. $\frac{60}{7}Pa$.

Answer 1

The correct option is B

Pa

This body could be taken as a cuboid of dimensions $2m\times 3m\times 4m$.

Therefore, the area of the top surface is $2m\times 3m=6m^2$.

The amount of force acting = $50N$

Thus, $pressure=\frac{Force}{Area}=\frac{50}{6}Pa$.​