A body of emissivity e - 0-75- surface area of 300 cm2 and temperature 227-C is kept in a room at temperature 27-C- Calculate the initial value of net power emitted by the body-

The correct option is C 69.4 WattUsing equation (13.3) P = e σ A (T^4 T^4_0) = (0.75) (5.67 × 10^ 8W/m^2 K^4) (300 × 10 4 m^2) × ...

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Standard XII

Physics

SHM expression

A body of emi...

Question

A body of emissivity (e = 0.75), surface area of $300 c m^{2}$ and temperature $227^{\circ}$ C is kept in a room at temperature $27^{\circ}$ C. Calculate the initial value of net power emitted by the body.

69.4 Watt

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9.4 Watt

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004 Watt

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69.19 Watt

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Solution

The correct option is C 69.4 Watt
Using equation (13.3)
$P = e σ A (T^{4} - T_{0}^{4})$
$= (0.75) (5.67 \times 10^{- 8} W / m^{2} - K^{4}) (300 \times 10 - 4 m^{2}) \times {(500 K)^{4} - (300 K)^{4}}$
= 69.4 Watt

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A body of emissivity (e = 0.75), surface area of 300cm2 and temperature 227∘C is kept in a room at temperature 27∘C. Calculate the initial value of net power emitted by the body.

The correct option is C 69.4 WattUsing equation (13.3)P=eσA(T4−T40)=(0.75)(5.67×10−8W/m2−K4)(300×10−4m2)×{(500K)4−(300K)4}= 69.4 Watt

A body of emissivity (e = 0.75), surface area of $300 c m^{2}$ and temperature $227^{\circ}$ C is kept in a room at temperature $27^{\circ}$ C. Calculate the initial value of net power emitted by the body.

The correct option is C 69.4 Watt
Using equation (13.3)
$P = e σ A (T^{4} - T_{0}^{4})$
$= (0.75) (5.67 \times 10^{- 8} W / m^{2} - K^{4}) (300 \times 10 - 4 m^{2}) \times {(500 K)^{4} - (300 K)^{4}}$
= 69.4 Watt