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Question

A body of mass 0.05 kg travelling with a velocity of 5 m/s make angle of 300 with the wall as shown. The body rebounds with the same speed making an angle of 300 with the wall. Find the contact force on the body in kN if the duration of contact is 1 ms.

A
0.20
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B
0.25
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C
0.35
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D
0.50
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Solution

The correct option is B 0.25


Change in momemtum is
Δp=m(vu)=0.05×(5/2(5/2))=0.25 Ns
Contact force, F=Δpt=0.251×103=0.25 kN

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