A body of mass 0.2 kg falls from a height of 10m to a height of 6m above the ground. Find the loss in potential energy taking place in the body. [g=10ms−2].
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Solution
Given : m=0.2kg,g=10ms−2,h1=10m,h2=6m. Loss in P.E. =mg(h1−h2) =0.2×10×10(10−6) =0.2×10×4=8J