A body of mass 0.2kg is rotated along a circle of radius 0.5m in the horizontal plane with uniform speed 3m/s. The centripetal force acting on that body is:
A
1.8N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
3.6N
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
18N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
36N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B3.6N Given, m=0.2kg, R=0.5m and v=3m/s Therefore, Fc=mv2R=(0.2)(0.32)(0.5)=3.6N