Question

A body of mass $0.2Kg$ is pressed into a vertical wall normally with a horizontal force $20N$.Coefficient of friction is $\mathrm{0.9.}$ Another horizontal force of $2N$ is applied on the body in the verticle plane. The frictional force acting on the body is $K\sqrt{2N}$. The value of $K$ is

Answer 1

Normal Force $=20N$

Frictional Force $=\mu N$

$=\left(0.9\right)20$

$=18$

$K\sqrt{2}=18$

$K=\frac{18}{\sqrt{2}}$