A body of mass $0.5 k g$ is moving with a constant velocity of $2 m s^{- 1}$ . In order to bring it to rest in a distance of $2 m$ , the work to be done is :

0.1 J

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1 J

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10 J

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100 J

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Solution

The correct option is B 1 J
According to law of conservation, Work Done = Change in kinetic Energy
$\Rightarrow W = Δ K . E$
$\Rightarrow W = \frac{1}{2} m v^{2}$
$= \frac{1}{2} (0.5) \times 2^{2} = 1 J$

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Similar questions

An object of mass, m is moving with a constant velocity, v. How much work should be done on the object in order to bring the object to rest?

0.5 k g

v = a x^{3 / 2}

a = 5 m^{- 1 / 2} s^{- 1}

x = 0

x = 2 m

5 m / s

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