A body of mass 0-5 kg is projected under gravity with a speed of 98 m-s at an angle of 30- with the horizontal- The change in momentum in magnitude of the body is

Change in momentum = 2 mu sinθ =2× 0.5×98× sin 30=45 N S ...

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Standard XIII

Physics

Summary for Time, Height and Range

A body of mas...

Question

A body of mass 0.5 kg is projected under gravity with a speed of 98 m/s at an angle of $30^{\circ}$ with the horizontal. The change in momentum (in magnitude) of the body is

24.5 N-s

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49.0 N-s

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98.0 N-s

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50.0 N-s

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Solution

The correct option is B
49.0 N-s

Change in momentum = $2 m u s i n θ$
$= 2 \times 0.5 \times 98 \times s i n 30 = 45 N - S$

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A body of mass 0.5 kg is projected under gravity with a speed of 98 m/s at an angle of 30∘ with the horizontal. The change in momentum (in magnitude) of the body is

The correct option is B 49.0 N-s Change in momentum = 2musinθ =2×0.5×98×sin 30=45 N−S

A body of mass 0.5 kg is projected under gravity with a speed of 98 m/s at an angle of $30^{\circ}$ with the horizontal. The change in momentum (in magnitude) of the body is

The correct option is B
49.0 N-s

Change in momentum = $2 m u s i n θ$
$= 2 \times 0.5 \times 98 \times s i n 30 = 45 N - S$