A body of mass 0-5 kg is projected under gravity with a speed of 98 m - s at an angle of 30- with the horizontal- The change in momentum in magnitudeof the body isA- 24-5 N - sB- 49-0 N - sC- 98-0 N - sD- 50-0 N - s

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Question

A body of mass 0.5 kg is projected under gravity with a speed of 98 m/s at an angle of $30^{\circ}$ with the horizontal. The change in momentum (in magnitude) of the body is

24.5 N–s

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49.0 N–s

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98.0 N–s

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50.0 N–s

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Solution

The correct option is B
49.0 N–s

Change in momentum between complete projectile motion = $2 m u s i n θ = 2 \times 0.5 \times 98 \times s i n 30^{\circ} = 49 N - s$

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A body of mass 0.5 kg is projected under gravity with a speed of 98 m/s at an angle of 30∘ with the horizontal. The change in momentum (in magnitude) of the body is

The correct option is B 49.0 N–s Change in momentum between complete projectile motion = 2mu sinθ=2×0.5×98×sin 30∘=49 N−s

A body of mass 0.5 kg is projected under gravity with a speed of 98 m/s at an angle of $30^{\circ}$ with the horizontal. The change in momentum (in magnitude) of the body is

The correct option is B
49.0 N–s

Change in momentum between complete projectile motion = $2 m u s i n θ = 2 \times 0.5 \times 98 \times s i n 30^{\circ} = 49 N - s$