Question

A body of mass 0.5 kg is rotated with uniform speed along vertical circle by means of light string. If tension in the string is 2.2 N when the body is crossing the highest point of vertical circle, the tension in the string when the body is crossing lowest point of is:

• A. 9.8 N
• B. 12N
• C. 15 N
• D. 19.6N

Answer 1

Answer: (B)

12N

$T_H=\frac{m{v}^2}{R}-mg{T}_L=\frac{m{v}^2}{R}+mg=T_H+2mg\Rightarrow T_L=2.2+\frac{1}{2}\times 0.5\times 9.8=12N$