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Question

A body of mass \(0. 5 ~π‘˜π‘”\) travels in a straight line with velocity \(𝑣 = π‘Žπ‘₯^{\dfrac{1}{2}}\) where \(π‘Ž = 5 π‘š^{\dfrac{1}{2}}S^{-1}\) . The work done by the net force during its displacement from to \(π‘₯ = 0\) \(π‘₯ = 2 π‘š\) is

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Solution

Given,

Mass of the body,\((π‘š) = 0. 5~ π‘˜π‘”\)

Velocity at any position \(𝑣 = π‘Žπ‘₯ ^{\dfrac{3}{2}}\)

Where \(π‘Ž = 5 π‘š^{-\dfrac{1}{2}}S^{-1}\)

From work-kinetic energy theorem

\(π‘Š = \Delta 𝐾 = 𝐾_{𝑓} βˆ’ 𝐾_{𝑖}\)

\(π‘Š =\dfrac{1}{2} π‘šπ‘£_ {𝑓}^{2} βˆ’ \dfrac{1}{2} π‘šπ‘£_ {i}^{2}\)

\(π‘Š =\dfrac{1}{2} π‘š (𝑣_{𝑓}{2} βˆ’ 𝑣_{𝑖}^{2}) \)

\(π‘Š = \dfrac{1}{2} \times0. 5\times\begin{Bmatrix}(5\times2^{\dfrac{3}{2}})^{2} βˆ’ (5\times2^{\dfrac{3}{2}})^{2}\end{Bmatrix}\)

\(π‘Š = \dfrac{1}{2} \times0. 5\times200\)

\(π‘Š = 50 ~𝐽\)

Final Answer: (𝑏)

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