A body of mass $1.5 k g$ is dropped from a height of $12 m$ . What is the force acting on it during its fall? $(g = 9.8 m s^{- 2})$

1.5 N

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9.8 N

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14.7 N

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147 N

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Solution

The correct option is C $14.7 N$
Force acting on the body during its fall = weight of the body.
So, $F = W = m \times g = 1.5 \times 9.8 = 14.7 N$
And this force is independent of the height of fall.

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A body of mass 1.5 kg is dropped from a height of 12 m. What is the force acting on it during its fall? (g=9.8 ms−2)

The correct option is C 14.7 NForce acting on the body during its fall = weight of the body.So, F=W=m×g=1.5×9.8=14.7 NAnd this force is independent of the height of fall.

A body of mass $1.5 k g$ is dropped from a height of $12 m$ . What is the force acting on it during its fall? $(g = 9.8 m s^{- 2})$

The correct option is C $14.7 N$
Force acting on the body during its fall = weight of the body.
So, $F = W = m \times g = 1.5 \times 9.8 = 14.7 N$
And this force is independent of the height of fall.