A body of mass 1 kg falls from a height of 5 m. How much energy does it possess at any instant? $(Take g = 9.8 m / s^{2})$

49J

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50J

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48J

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Solution

The correct option is A
49J

Given m = 1 kg, h = 5 m, $g = 9.8 m s^{- 2}$

According to the law of conservation of energy, the energy possessed by a body at any instant during free fall is same as the initial potential energy of the body.
So, Potential energy $= m g h = 1 \times 9.8 \times 5 = 49 J$

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A body of mass 1 kg falls from a height of 5 m. How much energy does it possess at any instant? (Take g=9.8 m/s2)

The correct option is A 49J Given m = 1 kg, h = 5 m, g=9.8 ms−2 According to the law of conservation of energy, the energy possessed by a body at any instant during free fall is same as the initial potential energy of the body. So, Potential energy =mgh=1×9.8×5=49 J

A body of mass 1 kg falls from a height of 5 m. How much energy does it possess at any instant? $(Take g = 9.8 m / s^{2})$