Question

A body of mass 1 Kg initially at rest explodes and breaks into three fragments of masses in the ration 1:1:3 The two pieces of equal mass fly off perpendicular to each other with a speed of $30m{s}^{-1}$ each. What is the velocity of the heavier fragment?

Answer 1

Given that,

Mass $m=1kg$

Velocity $v=30m/s$

According to law of conservation of linear momentum

$m_1{v}_1+m_2{v}_2+m_3{v}_3=0$

$30+30+3v_3=0$

$v_3=-20m/s^2$

Hence, the velocity of the heavier fragment is -$20m/s$