wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A body of mass 1 kg is moving with velocity 30 ms−1 due north. It is acted on by a force of 10 N due west for 4 seconds. Find the velocity of the body after the forces cases to act.

A
50 m/s;tan1(34)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
100 m/s;tan1(43)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
50 m/s;tan1(35)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
100 m/s;tan1(45)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 50 m/s;tan1(34)

Given,

Force act in direction of west F=10N

Velocity toward north Is Vn=30 ms1

Initial velocity in west direction is u=0m/s

Acceleration in west direction is a=FM=101=10m/s2

Final velocity after time 4 sec, in west direction is Vs=u+at=0+10×4=40m/s

Resultant velocity is VR=Vs2+Vn2=302+402 =50ms1

Direction of resultant velocity makes angle θ with the direction of force act.

tanθ=VnVs=3040=34

θ=tan1(34)

Hence the velocity of the body after the force ceases will be 50 m/s todards an angle θ=tan1(34) with the direction of force.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Circular Permutations
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon