Question

A body of mass 1 kg is subjected to a force of 20 N for 10 seconds after which the force ceases to act. What distance would it travel in the next 10 seconds.

Answer 1

For AB $a=\frac{20}{1}=20\frac{m}{s^2}$
$V_B=4+at=20\times 10=200\frac{m}{s}$

For BC a = 0, as~F = O
$\Rightarrow BC=V_B.t+O=200\times 10$
$=2000m=2km$