A body of mass 1 kg is thrown vertically up with an initial speed of 5 m/s. What is the magnitude and direction of force due to gravity acting on the body when it is at its highest point? Take $G = 9.8 n / k g$

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Solution

Mass of body = 1 kg
Initial speed= 5 m/s
Acceleration due to gravity = 9.8 N/Kg (Vertically downwards)
Force = Mass x Acceleration
Force = 1 x 9.8 = 9.8 N = 1 kgf
Therefore, 9.8 N or 1 kgf force acts vertically downwards.

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A body of mass 1 kg is thrown vertically up with an initial speed of 5 m/s. What is the magnitude and direction of force due to gravity acting on the body when it is at its highest point? Take G= 9.8 n /kg

Mass of body = 1 kg Initial speed= 5 m/s Acceleration due to gravity = 9.8 N/Kg (Vertically downwards) Force = Mass x Acceleration Force = 1 x 9.8 = 9.8 N = 1 kgf Therefore, 9.8 N or 1 kgf force acts vertically downwards.

A body of mass 1 kg is thrown vertically up with an initial speed of 5 m/s. What is the magnitude and direction of force due to gravity acting on the body when it is at its highest point? Take $G = 9.8 n / k g$

Mass of body = 1 kg
Initial speed= 5 m/s
Acceleration due to gravity = 9.8 N/Kg (Vertically downwards)
Force = Mass x Acceleration
Force = 1 x 9.8 = 9.8 N = 1 kgf
Therefore, 9.8 N or 1 kgf force acts vertically downwards.