A body of mass 1kg is thrown with a velocity of 10ms−1 at an angle of 60∘ with the horizontal. Its momentum at the highest point is:
A
2kgms−1
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B
3kgms−1
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C
4kgms−1
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D
5kgms−1
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Solution
The correct option is D5kgms−1 At the highest point, its velocity in the upward direction is zero but its velocity in the horizontal direction remains constant at every instant. Hence , only the horizontal component of velocity is responsible for the momentum of the body at the highest point.
Velocity of the body v=10ms−1
Velocity component of the body in the horizontal direction vH=vcos60o=10×0.5=5ms−1