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Question

A body of mass 1 kg is tied to one end of a string 2 m long. The other end is fixed and the body revolves in a horizontal circle. The maximum tension the string can bear is 80 kg wt. The maximum frequency the body can have (in rev/s) is (Take g=10 m/s2)

A
20
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B
π10
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C
10π
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D
None
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Solution

The correct option is C 10π
Given, mass of body (m)=1 kg
Length of string (l)=2 m
Maximum tension in string (Tmax)=80 kg wt=80×10=800 N

Since, tension provides necessary centripetal force.

Tmax=mlω2max
ω2max=Tmaxml
ωmax=Tmaxml=8002=20

Hence, the maximum frequency will be, (as ω=2πf)

fmax=202π=10π rev/sec

Hence option C is the correct answer

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