A body of mass 1kg moving with a velocity of 5m/s hits a spring on its free end. The other end of spring is fixed and it has a force constant of 400N/m. The body comes to rest after compressing the spring by 'x' m, the value of 'x' m is
A
0.55m
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B
0.35m
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C
0.45m
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D
0.25m
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Solution
The correct option is D0.25m Given u=5m/s Force constant k=400N/m let x be compression n the spring when body comes to rest. Applying law of conservation of energy, Kf−Ki=Ui−Uf (Kf=0 as final velocity is zero ,Ui=0 as spring is not streched initially) −12mu2=−12kx2 ∴x=u√mk=5√1400=520=0.25m