Question

A body of mass $1\text{kg}$ rests on a horizontal floor with which it has a coefficient of static friction$\frac{1}{\sqrt{3}}$. It is desired to make the body move by applying the minimum possible force $F\text{N}$. The value of $F$ will be . (Round off to the Nearest Integer)[Take g =$10{\text{ms}}^2]$

Answer 1

Given, $\mu =\frac{1}{\sqrt{3}},m=1\text{kg}$

We know that minimum possible force to move the object on a horizontal floor is given as$$F_{min}=\frac{\mu mg}{\sqrt{1+{\mu }^2}}$$$F_{min}=\frac{\frac{1}{\sqrt{3}}\times 1\times 10}{\sqrt{1+\frac{1}{3}}}$
$F_{min}=5\text{N}$