A body of mass 10 g is moving with a velocity of 50 m/s. On applying a constant force on the ball for 2 s, it acquires a velocity of 70 m/s. Calculate the magnitude of the force applied.

0.2 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.1 N

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.5 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.4 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 0.1 N
m = 10 g = 0.01 kg
u = 50 m/s, v = 70 m/s, t = 2s
Initial momentum = mu = 0.5 kg m/ s
Final momentum = mv = 0.7 kg m/ s
Rate of change of momentum = $\frac{(0.7 - 0.5) k g m s^{- 1}}{2 s}$
= 0.1 N

Suggest Corrections

Similar questions

Q. A body of mass 10 kg is moving with a velocity of 20 m/s. A force is applied to it so that in 10 s it acquires a velocity of 40 m/s. The force applied is:

A ball of mass 20 g is initially moving with a velocity of 100 $\frac{m}{s}$ . On applying a constant force on the ball for 0.5s, it acquires a velocity of 150 $\frac{m}{s}$ . Calculate the following:
(i) Initial momentum of the ball
(ii) Final momentum of the ball
(iii) Rate of change of momentum
(iv) Acceleration of the ball
(v) Magnitude of the force applied

A ball of mass 20 g is initially moving with a velocity of 100 $m s^{- 1}$ . On applying a constant force on the ball for 0.5s, it acquires a velocity of 150 $m s^{- 1}$ . Calculate the following : [5 MARKS]
(i) Initial momentum of the ball
(ii) Final momentum of the ball
(iii) Rate of change of momentum
(iv) Acceleration of the ball
(v) Magnitude of the force applied

A ball of mass 20 g is moving with a velocity of 40 $m s^{- 1}$ .On applying some constant force for 2 seconds it acquires a velocity of 80 $m s^{- 1}$ . What is the value of force?

A body of mass 10 kg mass is moving with a velocity of 15 metre per second . When a adore is applied on it , it's velocity becomes 30 metre per second after 10 sec. Calculate the applied force.

Join BYJU'S Learning Program

A body of mass 10 g is moving with a velocity of 50 m/s. On applying a constant force on the ball for 2 s, it acquires a velocity of 70 m/s. Calculate the magnitude of the force applied.

The correct option is B 0.1 N​m = 10 g = 0.01 kg​ u = 50 m/s, v = 70 m/s, t = 2s​ Initial momentum = mu = 0.5 kg m/ s​ Final momentum = mv = 0.7 kg m/ s Rate of change of momentum = (0.7–0.5)kgms−12s = 0.1 N​

The correct option is B 0.1 N
m = 10 g = 0.01 kg
u = 50 m/s, v = 70 m/s, t = 2s
Initial momentum = mu = 0.5 kg m/ s
Final momentum = mv = 0.7 kg m/ s
Rate of change of momentum = $\frac{(0.7 - 0.5) k g m s^{- 1}}{2 s}$
= 0.1 N