A body of mass 10 kg is being acted upon by a force 3t2 and an opposing constant force of 32N. The initial speed is 10ms−1. The velocity of body after 5s is:
A
14.5ms−1
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B
6.5ms−1
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C
3.5ms−1
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D
4.5ms−1
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Solution
The correct option is B6.5ms−1 F=ma ∴10a=3t2−3210dvdt=3t2−3210∫v10dv=∫50(3t2−32)dt10v−100=53−32×510v=100−35v=6.5m/s