A body of mass $10 k g$ is dropped to the ground from a height of $10$ metre. The work done by the gravitational force is $g = 9.8 \frac{m}{s^{2}}$ )

- 980 J

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- 490 J

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+ 980 J

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+ 490 J

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Solution

The correct option is C $+ 980 J$
Work done by the gravitational force $= m g h$
$= 10 \times 9.8 \times 10$
$= 980 J$

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