A body of mass 10 kg is dropped to the ground from a height of 10 metres. The work done by the gravitational force is $g = 9.8 m / s e c^{2}$

- 490 Joules

No worries! We‘ve got your back. Try BYJU‘S free classes today!

+ 490 Joules

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 980 Joules

No worries! We‘ve got your back. Try BYJU‘S free classes today!

+ 980 Joules

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D
+ 980 Joules

As the body moves in the direction of force therefore work done by gravitational force will be positive.

$W = F s = m g h = 10 \times 9.8 \times 10 = 980 J$

Suggest Corrections

Similar questions

A body of mass 10 kg is dropped to the ground from a height of 10 metres. The work done by the gravitational force is $g = 9.8 m / s e c^{2}$

10 kg

20 m

10 m/s

J

(g = 9.8 m / s e c^{2})

5 kg

10 m

(J)

^{'} A^{'}

^{'} B^{'}

g = 10 \frac{m}{s^{2}}

Join BYJU'S Learning Program