A body of mass $10 k g$ is moving with velocity $4 m / s$ . If P is the momentum associated with the body and K.E. is the kinetic energy. Then K.E. and P are:

80 J and 40 kg m/s

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200 J and 160 kg m/s

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400 J and 40kg m/s

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80 J and 160 kg m/s

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Solution

The correct option is A
80 J and 40 kg m/s

Kinetic energy $(K . E .) = \frac{1}{2} m v^{2}$
Momentum $(P) = m v$
So, $K . E . = \frac{1}{2} \times 10 \times$ $4^{2} = 80 J$
$P = 10 \times 4 = 40 k g m / s$

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A body of mass 10 kg is moving with velocity 4 m/s. If P is the momentum associated with the body and K.E. is the kinetic energy. Then K.E. and P are:

The correct option is A 80 J and 40 kg m/s Kinetic energy (K.E.)=12mv2 Momentum (P)=mv So, K.E.=12×10× 42=80 J P=10×4=40 kg m/s

A body of mass $10 k g$ is moving with velocity $4 m / s$ . If P is the momentum associated with the body and K.E. is the kinetic energy. Then K.E. and P are:

The correct option is A
80 J and 40 kg m/s

Kinetic energy $(K . E .) = \frac{1}{2} m v^{2}$
Momentum $(P) = m v$
So, $K . E . = \frac{1}{2} \times 10 \times$ $4^{2} = 80 J$
$P = 10 \times 4 = 40 k g m / s$