wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A body of mass 10 kg is acted upon by two perpendicular forces, 6 N and 8 N. The resultant acceleration of the body is

A
1 ms2, at an angle of tan1(43) with respect to 6 N force.
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
0.2 ms2, at an angle of tan1(43) with respect to 6 N force.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1 ms2, at an angle of tan1(34) with respect to 8 N force.
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
0.2 ms2, at an angle of tan1(34) with respect to 8 N force.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct options are
A 1 ms2, at an angle of tan1(43) with respect to 6 N force.
C 1 ms2, at an angle of tan1(34) with respect to 8 N force.
We have given mass m=10 kg, F2=8N, F1=6N.
Let's look at this figure to understand better.
Here, R is the resultant force
R=82+62=64+36=100=10 N
Now, we know F=ma or a=Fm=Rm=1010=1 ms2(1)
So, tan θ1=86=43; θ1=tan1 43 (2)
tan θ2=68=34; θ2=tan1 34 (3)

Hence from equations (1) & (2) option (a) is correct and from equations (1) & (3) option (c) also our acceleration is different hence options (b) & (d) are wrong.

flag
Suggest Corrections
thumbs-up
6
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Losing Weight Using Physics
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon