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Question

A body of mass 10 kg is placed on a smooth inclined plane as shown in the figure. The inclined plane is moved with a horizontal acceleration a.
The normal reaction between block and inclined plane is

A
92 N
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B
44 N
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C
56 N
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D
Can't be determined
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Solution

The correct option is C 56 N
FBD of block w.r.t. inclined plane
Fx=0Tcos37Nsin37ma=0
4T3N=200 ... (i)
Fy=0Ncos37+Tsin3710g=0
4N+3T=500 ... (ii)
By solving equation (i) & (ii), N=56 N

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