A body of mass $100 g$ is sliding on a inclined plane with an inclination of $60^{o} .$ What is the frictional force experienced, if coefficient of friction is $1.7 ?$
(Take $g = 10 m / s^{2}$ )

0.85 N

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0.96 N

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1.05 N

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1.145 N

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Solution

The correct option is A $0.85 N$
R.E.F image
Drawing Free
body diagram
of block
$= \frac{\sqrt{3}}{2} N$
Since, the net force normal to the plane
will be zero
$\Rightarrow N =⊥ c o s 60^{\circ} = \frac{1}{2} N$
we know that
$f = M N$
$= 1.7 \times \frac{1}{2}$
$\Rightarrow f = 0.85 N$

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