A body of mass 100g is made just to slide on a rough surface by applying a force of 0.8N. Then the coefficient of friction is $8 \times 10^{- x} .$ Find the value of x. (Take g =10 m s $^{- 2}$ ).

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Solution

If $μ$ be the coefficient of friction, the friction force $f = μ m g$
As the friction force opposes the motion, so in equilibrium, the friction force is equal to the applying force.
So, $μ m g = 0.8$ or $μ = \frac{0.8}{(0.1) (10)} = 0.8 = 8 \times 10^{- 1}$
Thus, the value of $x$ is $1$ .

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A body of mass 100g is made just to slide on a rough surface by applying a force of 0.8N. Then the coefficient of friction is 8×10−x. Find the value of x. (Take g =10 m s−2).

If μ be the coefficient of friction, the friction force f=μmgAs the friction force opposes the motion, so in equilibrium, the friction force is equal to the applying force. So, μmg=0.8 or μ=0.8(0.1)(10)=0.8=8×10−1Thus, the value of x is 1.

A body of mass 100g is made just to slide on a rough surface by applying a force of 0.8N. Then the coefficient of friction is $8 \times 10^{- x} .$ Find the value of x. (Take g =10 m s $^{- 2}$ ).

If $μ$ be the coefficient of friction, the friction force $f = μ m g$
As the friction force opposes the motion, so in equilibrium, the friction force is equal to the applying force.
So, $μ m g = 0.8$ or $μ = \frac{0.8}{(0.1) (10)} = 0.8 = 8 \times 10^{- 1}$
Thus, the value of $x$ is $1$ .