A body of mass 10kg is acted upon rest simultaneously by two forces 4N and 3N at right angle to each other. The kinetic energy of the body at the end of 10sec is

A)100j

B)300j

C)50j

D)125

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Solution

As the forces are acting at right angle to each other, net force on the body F=√42+32=5N

Kinetic energy of the body = work done = F×s=F×12at2=F×12(Fm)t2=5×12(510)(10)2=125J.

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A body of mass 10kg is acted upon rest simultaneously by two forces 4N and 3N at right angle to each other. The kinetic energy of the body at the end of 10sec is A)100j B)300j C)50j D)125

As the forces are acting at right angle to each other, net force on the body F=√42+32=5N Kinetic energy of the body = work done = F×s=F×12at2=F×12(Fm)t2=5×12(510)(10)2=125J.

A body of mass 10kg is acted upon rest simultaneously by two forces 4N and 3N at right angle to each other. The kinetic energy of the body at the end of 10sec is

A)100j

B)300j

C)50j

D)125

As the forces are acting at right angle to each other, net force on the body F=√42+32=5N

Kinetic energy of the body = work done = F×s=F×12at2=F×12(Fm)t2=5×12(510)(10)2=125J.