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Standard IX

Physics

Net Force

A body of mas...

Question

A body of mass 10kg is hanging from another body of mass 15kg. The combination is pulled up by a string with an acceleration of . $1.2 m^{- 2}$ Find the tensions (in N) at A and B points as shown in figure $(T a k e g = 9.8 m / s^{2})$ .

110,275

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250,100

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275,110

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100,250

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Solution

The correct option is C
275,110

$w e k n o w t h a t T = m (g + a) Tension at A is pulling the mass of 15+10 = 25kg S o T_{A} = 25 (g + a) = 25 [9.8 + 1.2]) = 275 N T_{B} = 10 [g + a] = 10 [9.8 + 1.2] = 110 N$

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A body of mass 10kg is hanging from another body of mass 15kg. The combination is pulled up by a string with an acceleration of . $1.2 m^{- 2}$ Find the tensions (in N) at A and B points as shown in figure $(T a k e g = 9.8 m / s^{2})$ .

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A body of mass 10kg is hanging from another body of mass 15kg. The combination is pulled up by a string with an acceleration of . 1.2m−2 Find the tensions (in N) at A and B points as shown in figure (Take g=9.8m/s2).

The correct option is C 275,110 we know that T=m(g+a)Tension at A is pulling the mass of 15+10 = 25kgSoTA=25(g+a)=25[9.8+1.2])=275NTB=10[g+a]=10[9.8+1.2]=110N

A body of mass 10kg is hanging from another body of mass 15kg. The combination is pulled up by a string with an acceleration of . $1.2 m^{- 2}$ Find the tensions (in N) at A and B points as shown in figure $(T a k e g = 9.8 m / s^{2})$ .

The correct option is C
275,110

$w e k n o w t h a t T = m (g + a) Tension at A is pulling the mass of 15+10 = 25kg S o T_{A} = 25 (g + a) = 25 [9.8 + 1.2]) = 275 N T_{B} = 10 [g + a] = 10 [9.8 + 1.2] = 110 N$