A body of mass $15 k g$ is raised from certain depth. If the work done in raising it by $10 m$ is $1620 J$ , its velocity at this position is $(g = 10 {m s}^{- 2})$ :

{2 m s}^{- 1}

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{4 m s}^{- 1}

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{1 m s}^{- 1}

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{8 m s}^{- 1}

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Solution

The correct option is B ${4 m s}^{- 1}$
work done=PE+KE
$1620 = m g h + \frac{m v^{2}}{2}$
$1620 = 15 \times 10 \times 10 + \frac{15 v^{2}}{2} = 1500 + \frac{15 v^{2}}{2}$
$v = 4 m / s$

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A body of mass 15 kg is raised from certain depth. If the work done in raising it by 10m is 1620J, its velocity at this position is(g=10ms−2):

The correct option is B 4 ms−1work done=PE+KE1620=mgh+mv221620=15×10×10+15v22=1500+15v22v=4m/s

A body of mass $15 k g$ is raised from certain depth. If the work done in raising it by $10 m$ is $1620 J$ , its velocity at this position is $(g = 10 {m s}^{- 2})$ :

The correct option is B ${4 m s}^{- 1}$
work done=PE+KE
$1620 = m g h + \frac{m v^{2}}{2}$
$1620 = 15 \times 10 \times 10 + \frac{15 v^{2}}{2} = 1500 + \frac{15 v^{2}}{2}$
$v = 4 m / s$