A body of mass $1 k g$ falls from a height of $5 m$ . How much energy does it possess at any instant? (Consider $g = 10 m s^{- 2}$ )

25 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

50 J

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Can not be determined with the help of given data

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $50 J$
$m = 1 k g, h = 5 m, g = 10 m s^{- 2}$
We know that total energy of a body is always constant according to the principle of conservation of energy.
So, energy possessed by the body at any instant $=$ initial potential energy of the body $= m g h = 1 \times 10 \times 5 = 50 J$

Suggest Corrections

Similar questions

A body of mass 5 kg falls from a height of 10 m to 4m. Calculate:

(i) the loss in potential energy of the body, and (ii) the total energy possessed by the body at any instant? (Take g=10 m $s^{- 2}$ ).

10 k g

5 m

s^{- 2}

10 m s^{- 2}

1 k g

5 m

1 k g

5 m

g = 10 m s^{- 2}

Join BYJU'S Learning Program