A body of mass 2 kg has an initial velocity vi=(^i+^j)ms−1. After collision with another body its velocity becomes vf=(5^i+6^j−^k)ms−1. If the impact time is 0.02 s, the average force of impact on the body (in newton) is
A
50(4^i+5^j+^k)
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B
50(4^i−5^j−^k)
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C
100(4^i+5^j−^k)
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D
100(4^i+5^j−^k)
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Solution
The correct option is D100(4^i+5^j−^k) Change in momentum = m(vf−vi)=2kg(5^i+6^j−^k)ms−1−2kg(^i+^j)ms−1=2(4^i+5^j−^k) Average force = changeinmomentumtimeofimpact =2(4^i+5^j−^k)0.02s=100(4^i+5^j−^k) Hence the correct choice is (d).