The correct option is D 2 N
Given:
Initial velocity, u=2 ms−1
Stopping distance, s=2 m
As the object comes to rest, final velocity v=0ms−1
Mass, m=2 kg
Let the acceleration be a
From the third equation of motion, we have
v2−u2=2as
a=v2−u22s=02−222×2=−1 ms−2
From Newton's second law of motion, force on the body is:
F=m×a
F=2×−1=−2 N
It may be noted that the negative sign implies that the force is acting in a direction opposite to the motion of the object.