Question

A body of mass 2 kg having a velocity of 2 $m/s$ is brought to rest within a distance of 2 m. Find the force acting on the body.

• A. 8 N
• B. 1 N
• C. 4 N
• D. 2 N

Answer 1

The correct option is D 2 N

Acceleration :

$v^2$ = $u^2$ - $2as$ ($v$ is final velocity, $u$ is initial velocity and a is acceleration)

V = 0 $m/s$; as the object comes to rest

U = 2 $m/s$ and s = 2 m

Thus, acceleration = 1 $m/s$

$F=m\times a$;

$F=2\times 1=2Kg\frac{m}{s^2}$