Question

A body of mass 2 kg having a velocity of 2 $m{s}^{-1}$ is brought to rest within a distance of 2m. The force acting on the body is

• A. 8 N
• B. 1 N
• C. 4 N
• D. 2 N

Answer 1

The correct option is D 2 N

Given mass of body m = 2 kg, initial velocity u = 2 $m{s}^{-1}$, final velocity v = 0 and distance s = 2m.

Using equation of motion

$v^2=u^2-2as$ (Since body is retarding)

$0=2^2-2\times a\times 2$

Thus, acceleration = 1 $m{s}^{-2}$

We know F = ma;

F = $2\times 1$ = 2 N