A body of mass 2 kg is moving towards north with a speed of 4ms−1. A force of 4 N is applied on it towards west. Displacement of the body 2 seconds after the force is applied
A
4√5m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
4√2m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
5√4m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
5√2m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A4√5m Displacement due north will be XN=uNt=4×2=8m
Acceleration due West will be a=4N2kg=2m/s2
so the displacement due west will be XW=uWt+12at2=0+22=4m
As north and west are perpendicular to each other so net displacement will be X=√X2N+X2W=√64+16