A body of mass $2 k g$ is thrown upward with initial velocity $20 m / s$ . After $2 s$ find its kinetic energy will be: $(g = 10 m / s^{2})$

400 J

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200 J

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100 J

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Zero

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Solution

The correct option is D Zero
In $2 s, v = 20 - 10 \times 2 = 0$
As, K.E $= \frac{1}{2} m v^{2}$
So, kinetic energy at the highest point will be zero.

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A body of mass 2 kg is thrown upward with initial velocity 20 m/s. After 2 s find its kinetic energy will be: (g=10 m/s2)

The correct option is D ZeroIn 2s,v=20−10×2=0As, K.E=12mv2So, kinetic energy at the highest point will be zero.

A body of mass $2 k g$ is thrown upward with initial velocity $20 m / s$ . After $2 s$ find its kinetic energy will be: $(g = 10 m / s^{2})$

The correct option is D Zero
In $2 s, v = 20 - 10 \times 2 = 0$
As, K.E $= \frac{1}{2} m v^{2}$
So, kinetic energy at the highest point will be zero.