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Standard XII

Physics

Acceleration

A body of mas...

Question

A body of mass 2 kg moving on a horizontal surface with an initial velocity of 4 m/s comes to rest after 2 s. If one wants to keep this body moving on the same surface with a velocity of 4 m/s, the force required is:

8 N

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4 N

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Zero

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2 N

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Solution

The correct option is B 4 N
given $u = 4 \frac{m}{s}$ & $t = 2 s$
$v = 0$
from $v = u + a t$
$u = - a t$
$4 = - a (2)$
$a = - 2 \frac{m}{s^{2}}$ as the acceleration direction is opposite the sign is negative
$F = m a = 2 (2) = 4 N$

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A body of mass 2 kg moving on a horizontal surface with an initial velocity of 4 m/s comes to rest after 2 s. If one wants to keep this body moving on the same surface with a velocity of 4 m/s, the force required is:

The correct option is B 4 Ngiven u=4ms & t=2sv=0fromv=u+atu=−at4=−a(2)a=−2ms2 as the acceleration direction is opposite the sign is negativeF=ma=2(2)=4N

The correct option is B 4 N
given $u = 4 \frac{m}{s}$ & $t = 2 s$
$v = 0$
from $v = u + a t$
$u = - a t$
$4 = - a (2)$
$a = - 2 \frac{m}{s^{2}}$ as the acceleration direction is opposite the sign is negative
$F = m a = 2 (2) = 4 N$