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Question

A body of mass 2 kg moving on a horizontal surface with speed vi=1ms1 enters a rough patch ranging from x = 0.5 m to x = 1.5 m. If the body comes to rest after crossing the patch, then find the retarding force on body.

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Solution

: w=ΔkE

f.s=12m(v2u2)

f×(1.50.5)=12×2×(01)

f=1N


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