Question

A body of mass 2 kg starts with an initial velocity 5 m/s. If the body is acted upon by a time dependent force (F) as shown in the figure, then work done on the body in 20 s is

Answer 1

Work done on body is $\int Fdt$ which can be calculated using area of graph

$\Rightarrow WorkDone=\int Fdt=20\left(5\right)+\frac{1}{2}\left(20\right)\left(5\right)-\frac{1}{2}\left(20\right)\left(10\right)$

$\Rightarrow WorkDone=50J$